Question

Find the area of an isosceles triangle in which each of the equal sides measures 30cm and the third side is 48 cm long.

Answer 1

Answer:

QUESTION:

Find the area of an isosceles triangle in which each of the equal sides measures 30cm and the third side is 48 cm long.

SOLUTION:

Let a=30 cm , b=30 cm , c=48 cm

$S = \frac {a + b + c}{2} = \frac {30 + 30 + 48}{2} \\ \: \: \: \: = 54 \: cm$

Area of traingle:

$\sqrt{ S(s - a)(s - b)(s - c)} \\ \sqrt{ 54(54 - 30)(54 - 30)(54 - 48)} \\ \sqrt{ 54(24)(24)(6)} \\ \sqrt{6 \times 3 \times 3 \times 6 \times 4 \times 6 \times 4 \times 6} \\ = 432 \: cm {}^{2}$

$\bf \: {THANK \: YOU}$