Math, asked by attharvguptab, 10 hours ago

find the area of an isosceles triangle in which each of the equal sides measures 30 cm and the third side is 48 cm long.​

Answers

Answered by lechusunitha
0

Answer:

432 CM ^2

Step-by-step explanation:

Answered by neth2444
0

Answer:

612cm square

hope it helps!

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thanks!!!

Step-by-step explanation:

we'll use Heron's formula:

\sqrt{s(s-a)(s-b)(s-c)}

where s = perimeter/2 = 108/2 = 54; a = side1 = 30, b = 30 ; c = 48

\sqrt{54(54-30)(54-30)(54-48)} \\= \sqrt{54*34*34*6} \\= \sqrt{2*3*3*3*17*17*2*2*2*3} \\= 3*3*2*2*17\\= 612

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