Question

find the area of an isosceles triangle in which each of the equal sides measures 30 cm and the third side is 48 cm long.​

Answer 1

Answer:

432 CM ^2

Step-by-step explanation:

Answer 2

Answer:

612cm square

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Step-by-step explanation:

we'll use Heron's formula:

$\sqrt{s(s-a)(s-b)(s-c)}$

where s = perimeter/2 = 108/2 = 54; a = side1 = 30, b = 30 ; c = 48

$\sqrt{54(54-30)(54-30)(54-48)} \\= \sqrt{54*34*34*6} \\= \sqrt{2*3*3*3*17*17*2*2*2*3} \\= 3*3*2*2*17\\= 612$