find the area of an isosceles triangle in which each of the equal sides measures 30 cm and the third side is 48 cm long.
Answers
Answered by
0
Answer:
432 CM ^2
Step-by-step explanation:
Answered by
0
Answer:
612cm square
hope it helps!
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Step-by-step explanation:
we'll use Heron's formula:
where s = perimeter/2 = 108/2 = 54; a = side1 = 30, b = 30 ; c = 48
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