Question

Find the area of an isosceles triangle in which each of the equal sides measure 30 cm and the third side is 48 centimetre long

Answer 1

Draw a line in centre of triangle
now we have 2 right angles with base 48 ÷ 2 = 24 cm
and Hypotaneous = 30 cm
Lets find Perpendicular with Pythagoras

H² = P² + B²
P² = H² - B²
= 30² - 24²
= 900 - 576
= 324
P = √324
P = 18 cm

Area of right angle = 1 ÷2 x base x height
= 1/2 x 24 x 18
= 216 cm²
and 2 x 216 = 532 cm².

Hope you are happy

Answer 2

Step-by-step explanation:

Formula of height = square root of a square

= b square /4

a =one equal side

b= height = 18cm

base = 48cm

equal side =30.cm

Area = 1/2 ×base × height

= 1/2 ×48×18

= 24×18

= 432 cm²

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