Question

Find the area of an isosceles triangle of equal sides 9cm and base 12cm

Answer 1

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Area =

Using herons formula

Refer to the attachment

@ Prabhudutt

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Answer 2

Area =1/2×base×height


height(AC)
AD²=CD²+AC²
9²=6²+AC²
81-36=AC²
45=AC²
3√5=AC

Area=1/2×BD×AC
Area=1/2×12×3√5
Area=6×3√5
Area=40.24cm²