Find the area of an isosceles triangle, the measure of one of its side being 'b' and the third side 'a'.
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Heya
In an isosceles triangle the altitude and the median drawn to the non-equal side are the same.
Let us take the side 'a' as the base and the altitude/median drawn to it as the height.
Height =√ [b²- (a/2)²]
= √ [b²-a²/4]
= √ [(4b²-a²)/4]
√ [(4b²-a²)] / 2
Area = 1/2 × base × height
Area = 1/2 × a² × √ [(4b²-a²)] / 2
Area = a²√[4b²-a²] / 4
In an isosceles triangle the altitude and the median drawn to the non-equal side are the same.
Let us take the side 'a' as the base and the altitude/median drawn to it as the height.
Height =√ [b²- (a/2)²]
= √ [b²-a²/4]
= √ [(4b²-a²)/4]
√ [(4b²-a²)] / 2
Area = 1/2 × base × height
Area = 1/2 × a² × √ [(4b²-a²)] / 2
Area = a²√[4b²-a²] / 4
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