find the area of an isosceles triangle the measure of one of its equal side being 10 cm and the third side is 6 CM ? plz help
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Step-by-step explanation:
given,
∆ ABC is an isoscles ∆
so, AB = BC = 10 cm
AC = 6 cm
perimetre = AB + BC + AC
= 10 +10 +6
= 26 cm
semi -peri..= p/2
= 26/2
= 13 cm
area = √ s(s - a) (s - b) (s - c)
= √ 13 (13 - 10)(13 - 10)(13 - 6)
=√13×3×3×7
= 3×√13×7
= 3√91 cm^2
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