Math, asked by bishwajyotisinha411, 1 month ago

find the area of an isosceles triangle which has base 12 cm and equal sides are 10cm each​

Answers

Answered by ASMAJEBIN
1

Answer:

A=48cm²

A=48cm²a Side

A=48cm²a Side 10

A=48cm²a Side 10cm

A=48cm²a Side 10cmb Base

A=48cm²a Side 10cmb Base 12

A=48cm²a Side 10cmb Base 12cm

Answered by jagtapraghav9
2

Answer:

Triangle are formula is 1/2×height×base

we assume that height = 12cm

base =10cm

 \frac{1}{2}  \times 12 \times 10

 \frac{1}{2} \times 120 = 60

area \: of \: isosceles \: tringle \: is \: 60cm

Step-by-step explanation:

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