Question

Find the area of an isosceles triangle which has:: base 16cm and equal sides 17cm each​

Answer 1

Answer:

120

Step-by-step explanation:

$a=16 b=17 c=17$

By heron's formula

$\sqrt{s(s-a)(s-b)(s-c)}$

where  

$s=\frac{a+b+c}{2}$

∴$s=$$16+17+17/2=25$

$\sqrt{s(s-a)(s-b)(s-c)}$  $(s-a=25-16=9)(s-b=25-17=8)(s-c=25-17=8)$

$\sqrt{25*9*8*8}$

⇒$\sqrt{5^{2} *3^{2}*8^{2}$

=  $5*3*8$

=  $120$