Math, asked by sonu6745, 1 year ago

Find the area of an isosceles triangle
which has perimeter 50 m and whose
unequale side is 10​

Answers

Answered by Anonymous
1

Answer:

P=50 m

Unequal side = 10 m

Ther fore same sides added= (50-10)/2 m

=40/2 m

= 20 m

Therefore equal sides length is 20 m each.

Answered by rajeevnair1995
1

Answer:

25(15)^1/2 or 25 times square root of 15.

Step-by-step explanation:

unequal side + 2 equal sides gives us 50.

equal sides will be 20.

Area for isoscelels triangle = (b/4)* square root(4a^2 - b^2) where a is the length of equal side and b of the unequal.

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