Find the area of an isosceles triangle
which has perimeter 50 m and whose
unequale side is 10
Answers
Answered by
1
Answer:
P=50 m
Unequal side = 10 m
Ther fore same sides added= (50-10)/2 m
=40/2 m
= 20 m
Therefore equal sides length is 20 m each.
Answered by
1
Answer:
25(15)^1/2 or 25 times square root of 15.
Step-by-step explanation:
unequal side + 2 equal sides gives us 50.
equal sides will be 20.
Area for isoscelels triangle = (b/4)* square root(4a^2 - b^2) where a is the length of equal side and b of the unequal.
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