Question

find the area of an isosceles triangle which has these 16 cm and equal sides are 17 cm each​

Answer 1

$\huge \fbox \green{Answer}$

We have,

Three sides13cm,13cm and 20cm.

By using Heron's formula

We need to get the semi-perimeter

s=

2

a+b+c

=

2

13+13+20

=

2

46

=23

Now,

put the heron's formula,

s=

s(s−a)(s−b)(s−c)

=

23(23−13)(23−13)(23−20)

=

23×10×10×3

=10

23×3

=83.07cm

2

Answer 2

Base = 16 cm

Lengh of both equal side = 17 cm

We will use Herons's formula to find the area

• a = 16 cm
• b = 17 cm
• c = 17 cm

Halfperimeter (s) = 1/2 × (16 + 17 +17) = 50/2 = 25 cm

using Heron's formula

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ \sqrt{25(25 - 16)(25 - 17)(25 - 17)} \\ \\ \sqrt{25 \times 9 \times 8 \times 8} \\ \\ = 600 \:cm^{2}$

.°. The area of given triangle is 600 cm²