Question

Find the area of an Isosceles triangle whose base is 10cm and one of its equal sides is 13 cm​

Answer 1

Answer:

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Step-by-step explanation:

the area of a triangle = side+side+side

so isoceles triangle means two sides equal and one side I'd different so it will be

13+13+10= 36

this is your answer

Answer 2

★ Given:-

• Base of an Isosceles Triangle = 10 cm
• Sides = 13 cm

★ To Find:-

The area of the Triangle.

★ Solution:-

Let ABC be the iscolesces triangle where AB = AC = 13 cm

Referring to the figure, AD ⊥ BC

BD = DC = 12 cm

In right angled ∆ABD, by Pythagoras theorem,

We have  ⠀⠀⠀⠀⠀⠀AB² = AD² + BD²

⇒  ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀13² = AD² + 12²

or  ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀AD² = 13² - 12²

  ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀AD² = 169 - 144 = 25

  ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀  AD² = 5²

∴ AD = 5 cm

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  ★ Remember:-

$\red{\underline{\boxed{\sf{ \star \: Area \: of \: a \: Triangle = \frac{1}{2} \times l \: \times b \: \star}}}}$

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Important Formulas:-

★ Area of a square = side × side = (side)²

★ Area of a rectangle = Length × breadth = l × b

★ Area of a circle = π × (Radius) = πr²

$\small{{{\sf{ π = \frac{22}{7} }}}}$

★ Surface area of a cylinder = 2π × Radius × height = 2πrh

★ Surface area of a sphere = 4π × (Radius)² = 4πr²