Question

Find the area of an isosceles triangle whose base is 12 cm and the length of each equal side is 10 cm.​

Answer 1

Answer:

Step-by-step explanation:

Base = 12cm

Length of equal sides = 10cm

Area of Triangle  =  1/2 x Base x Height

Height^2 = Hypotenuse^2 (10cm) - 1/2 base^2 =

            = 100 - 6^2

            = 100 - 36 = 64

Height = Square Root of 64 = 8 x 8 = 8

Area = 1/2 x 10 x 12

        = 5 x 12

        = 60 cm^2