Find the area of an isosceles triangle whose Base is 16 cm and one of its equal side is 10 cm
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It is explained by herons formula
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hey mate here's ur answer
let's see ur answer
___________
perimeter of triangle = 10+10+16 = 36
semi perimeter = 36/2=18
Now , using heron's formula :-
area = √s(s-a)(s-b)(s-c)
√18(18-10)(18-10)(18-16)
√18×8×8×2
√2×3×3×4×2×4×2×2
2×2×3×4
48cm^2
hope it helps
let's see ur answer
___________
perimeter of triangle = 10+10+16 = 36
semi perimeter = 36/2=18
Now , using heron's formula :-
area = √s(s-a)(s-b)(s-c)
√18(18-10)(18-10)(18-16)
√18×8×8×2
√2×3×3×4×2×4×2×2
2×2×3×4
48cm^2
hope it helps
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