Math, asked by khushi1912, 1 year ago

find the area of an isosceles triangle whose base is 18cm and one of its equal sided is 15cm

xyz162: area of triangle= root over (s-a)(s-b)(s-c) .first we find s . s=a+b+c/2 ok .so,s=18+15+15/2=24.now area of triangle=rootover 24(24-18)(24-15)(24-15)=rootover 24(6)(9)(9) now we find the prime factor so, the prime factor is rootover 2×2×2×3×2×3×3×3×3×3=now we make the pair bcoz it is in the root ok.so,2×2×3×3×3=4×9×3=108. so, the area of triangle is 108m^2

rs7908720: Yes

Answers

Answered by Mattupallinikitha

here is the answer using helens formula

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Mattupallinikitha: sorry for the wrong calculation

khushi1912: it's okay

Answered by rs7908720

Area of triangle =
$\sqrt{s(s - a)(s - b)(s - c)}$
S=a+b+c/2
a=18 b=15 c=15
S=48/2
s=24
$\sqrt{24(24 - 18)(24 - 15) (24 - 15)}$
$\sqrt{24 \times 6 \times 9 \times 9}$
$\sqrt{6 \times 2 \times 2 \times 6 \times 9 \times 9}$
=6*2*9
=
${108cm }^{2}$

Hope it help

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