find the area of an isosceles triangle whose base is 8 centimetre and length of each equal side is 5cm
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ANSWER ==> 12 CM²
SO, SIDES ARE 8 CM , 5 CM , 5 CM
BY HERON'S FORMULA
S = A+B+C/2 ==> 8+5+5/2 ==> 9
==>√9×√(9-8) × √9-5 ×√9-5
==> √9×1×4×4
==> √3×√3×√4×√4
==> 3×4 ==> 12 CM²
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