Question

Find the area of an isosceles triangle whose base is 8 cm long and the length of each of the equal side is 5 cm.​

Answer 1

Answer:

12 cm^2

Step-by-step explanation:

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Answer 2

Answer:

let base be BC=8cm and AC=AB=5cm. construction : draw AD perpendicular to side BC. DC =1/2BC = 1/2 8= 4 CM. In triangle ADC , angle ADC =90. By Pythagoras Theorem, AC2=AD2+DC2. 52=42 + AD2. AD2 = 25-16 =9. AD=3cm. area of triangle ABC =1/2 AD BC. = 1/2 into 3 into 8 = 12 sq. CM. area of given triangle is 12 sq. cm