Question

find the area of an isosceles triangle whose base
is 8cm and
length of equal dides is 5cm​

Answer 1

Answer:

If we draw the altitude of an isoceles triangle , then it bisects the base .

So let ABC be an isoceles triangle with base BC = 8 cm, and AB =AC= 5 cm .

Draw altitude AD.

So, BD = CD = 4 cm .

Now, ADB is a right triangle, by pythogoras theoram:

AD = 3 cm .

Thus, area of ABC = 1/2× BC × AD = 1/2× 8×3 = 12cm^2.

Answer 2

Answer:

12cm2

Step-by-step explanation:

the correct answer is 12cm^2

do it by drawing altitude in isosceles triangle