Find the area of an isosceles triangle whose base is 8cm and perimeter 20cm.
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3
Answer:
8√5
Step-by-step explanation:
Perimeter of an isosceles ∆
= Sum of all sides (a+b+c)
= 20cm
The base(non- equal side) measure
= 8cm
let the other two equal sides be
= x
According to the question
- x + x + 8 = 20
- 2x = 20-8
- x = 12/2
- x = 6cm
Therefore,
Area of the isosceles triangle
= _______________
√s (s - a) (s - b) (s - c)
Here, a = 6cm, b = 6cm and c = 8cm
s = semi- perimeter = 20/2
= 10cm
_______________________
√10 (10-6) (10-6) (10-8)
______________________
√ 10 × 4 × 4 × 2
_____________________
4 √ 2×5× 2
4×2 √5
8√5
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