Find the area of an isosceles triangle, whose base is 8cm and length of each equal side is 5ccm.
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Answered by
4
Answer:
12cm²
Step-by-step explanation:
A=bhb
2
hb=a2﹣b2
4
Solving forA
A=1
4b4a2﹣b2=1
4·8·4·52﹣82=12cm²
Hope it will help you
Answered by
6
Answer:
you can try by this process
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