find the area of an isosceles triangle whose base is a ans equal sides are b
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Step-by-step explanation:
We know, in isosceles triangle altitude , is bisect to base.
so, Altitude = √(side length of equal side )² - (base/2)² } = √(b² -a²/4)
now, area of isosceles triangle = 1/2 × altitude × base
= 1/2 × √(b² - a²/4) × a
= 1/4 × a × √(4b² - a²)
4.6
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