Math, asked by matthewalexander, 11 months ago

find the area of an isosceles triangle whose each equal side is 5 cm and third sideis 8 cm​

Answers

Answered by Blue14
0

Answer: 12cm²

Step-by-step explanation:

If we draw the altitude of an isoceles triangle , then it bisects the base .

So let ABC be an isoceles triangle with base BC = 8 cm, and AB =AC= 5 cm .

Draw altitude AD.

So, BD = CD = 4 cm .

Now, ADB is a right triangle, by pythogoras theoram:

AD = 3 cm .

Thus, area of ABC = 1/2× BC × AD = 1/2× 8×3 = 12cm^2.

Similar questions