find the area of an isosceles triangle whose each equal side is 5 cm and third sideis 8 cm
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Answer: 12cm²
Step-by-step explanation:
If we draw the altitude of an isoceles triangle , then it bisects the base .
So let ABC be an isoceles triangle with base BC = 8 cm, and AB =AC= 5 cm .
Draw altitude AD.
So, BD = CD = 4 cm .
Now, ADB is a right triangle, by pythogoras theoram:
AD = 3 cm .
Thus, area of ABC = 1/2× BC × AD = 1/2× 8×3 = 12cm^2.
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