Question

find the area of an isosceles triangle whose each side equal to 18cm and baseis 28cm find area of a triangle take root2=1.41
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Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

area =  \\  \sqrt{s(s - a)(s - b)(s - c)}  \\ s =  \frac{a + b + c}{2}  \\

s =  \frac{18 + 28 + 28}{2}  \\  =  \frac{84}{2}  = 42

area =  \\  \sqrt{42(42 - 18)(42 - 18)(42 - 28)}  \\  \sqrt{42 \times 24 \times 24 \times 14}  \\   17 \times 24 \sqrt{3}  \\ 336 \sqrt{3}  \\

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Step-by-step explanation: