Question

Find the area of an isosceles triangle whose each two sides are 5cm and 6cm

Answer 1

Answer:

hey mate your answer is here

Step-by-step explanation:

HEIGHT OF THE TRIANGLE = [5^2 - 3^2]^0.5 = 4

AREA OF THE TRIANGLE = 0.5*6*4 = 12 sqcm

ANOTHER WAY : PERIMETER = 5+5+6 = 16; SEMIPERIMETER = s = 16/2 = 8  

AREA = [ 8*(8–5)*(8–5)*(8–6)]^0.5 = [8*3*3*2]^0.5 = 144^0.5 = 12 sqcm

Hope it help u

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