Find the area of an isosceles triangle whose equal side measure 13 cm and whose base measure 20 cm
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We have,
Three sides13cm,13cm and 20cm.
By using Heron's formula
We need to get the semi-perimeter
s= a+b+c/2 = 13+13+20/2
= 46/2 =23
Now,
put the heron's formula,
s= √s(s−a)(s−b)(s−c)
= √23(23−13)(23−13)(23−20)
= √23×10×10×3
=10 √23×3
=83.07cm²
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