Question

find the area of an isosceles triangle whose equal sides measure 10 cm each and the third side is 12 centimetre​

Answer 1

here is your answer

Step-by-step explanation:

hope you like it

Answer 2

The area of an isosceles triangle is 48 sq. cm.

Step-by-step explanation:

Since we have given that

Measure of equal sides = 10 cm

Measure of third side = 12 cm

so, we need to find the area of an isosceles triangle.

Semi perimeter s = $\dfrac{a+b+c}{2}=\dfrac{10+10+12}{2}=\dfrac{32}{2}=16\ cm$

So, Area of isosceles triangle would be

$\sqrt{s(s-a)(s-b)(s-c)}\\\\=\sqrt{16(16-10)(16-10)(16-12)}\\\\=\sqrt{16\times 6\times 6\times 4}\\\\=\sqrt{2304}\\\\=48\ cm^2$

Hence, the area of an isosceles triangle is 48 sq. cm.

# learn more:

Find the area of an isosceles triangle each of whose equal sides measures 13 cm and whose base measure to centimetre

https://brainly.in/question/5702343