Question

find the area of an isosceles triangle whose equal sides measure 5 cm each and height corresponding to the third side is 4 cm​

Answer 1

Answer:

12cm^

Step-by-step explanation:

Let the traingle be ABC

and the equal sides be AB and AC

therefore they measures 5cm

let the hieght be AD = 4cm

The perpendicular from vertex to opposite side bisects the side

therefore BD = CD

In traingle ABD , AD is perpendicular to BC

By Pythagoras theorem

AB^=BD^ + AD^

(5cm)^=BD^+ (4cm)^

25cm^=BD^+16cm^

9cm^= BD^

3cm = BD

BC = 2BD = 6cm

Area or triangle ABC =1/2 Base ×hieght

= 1/2 × 6cm × 4cm

= 12cm^

hope it will help

Answer 2

Answer:

2 root 5^2-4^2

2root 25-16

2root9

2root3*3

2*3=6

area of triangle=1/2*base*height

1/2*6*4

=12 answer