Question

Find the area of an isosceles triangle whose equal sides measure 5 cm each and height
corresponding to the third side is 4 cm.
of the sides of a triangle are in the ratio 3.4.5 and its perimeter is 60 cm. Fi​

Answer 1

i)

Solution:

We Know That,

Area of Isosceles Triangle: (1/2)×bh

Given:

Base = 6cm,

Corresponding Height = 4cm.

Solution:

Area of Isosceles Triangle

= (1/2)×bh

= (1/2)×6cm×4cm = 12cm²

Conclusion:

Area of Isosceles Triangle = 12cm²

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ii)

Solution:

Let a,b,c are the sides of given triangle.

Given:

Sides of a triangle are in ratio 3:4:5

So, a:b:c = 3:4:5 = k, a= 3k, b= 4k, c= 5k

Perimeter of triangle = 60cm.

We know that,

Perimeter of triangle = sum of all sides.

So, 60cm = a+b+c

60cm = 3k+4k+5k

60cm = 12k → k = 5.

Conclusion:

The sides of given triangle are

15cm, 20cm, 25cm.

REQUEST:

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