Question

find the area of an isosceles triangle whose equal sides are 12 cm each and the perimeter is 30cm
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Answer 1

Answer:

perimeter of isosceles triangle is 30

sum of all sides=30

12+12+x=30

x=30-24

x=6

And then you find area

Answer 2

Given that : Base of Isosceles triangle = 12cm

and Perimeter = 30cm

Then, Area of Isosceles triangle :

$\frac{1}{4} </strong><strong>B</strong><strong> \sqrt{</strong><strong>P</strong><strong>(</strong><strong>P</strong><strong> - 2b)} \\ \\ = > \frac{1}{4} \times 12 \sqrt{30(30 - 2 \times 12)} \\ \\ \\ = > 3 \sqrt{30 (30 - 24)} \\ \\ = > 3 \sqrt{30 \times 6} \\ \\ = > 3 \times 6 \sqrt{5} \\ \\ = > 18 \times 2.236 = 40.248$

So, the area of Isosceles triangle will be 40.249(approx).

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