find the area of an isosceles triangle whose equal sides are A and unequal side is b by using heron's formula
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Length of sides=a,a,b
Heron's formula
=√s(s-a)(s-b)(s-c)
where s=(a+b+c)/2
Substituting values
s=(a+a+b)/2
=(2a+b)/2
√(2a+b)(2a+b-a)(2a+b-a)(2a+b-b)
=√(2a+b)(a+b)²(2a)
=(a+b)√4a²+b
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Refer to the diagram attached below
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