find the area of an isosceles triangle whose equal sides are 12 cm each and the perimeter is 30 cm
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Answered by
24
area of issoceles traingle is = 1/2 ×base× height.
parimeter of issoceles traingle = l×b=30
so , l=30/b=30/12 = 5/2= 2.5 cm
so area =1/2×2.5×12= 15 cm.
parimeter of issoceles traingle = l×b=30
so , l=30/b=30/12 = 5/2= 2.5 cm
so area =1/2×2.5×12= 15 cm.
Answered by
76
if the equal sides are 12 cm each, then
perimeter = sum of all sides
here, 30= 12+12+(non-parallel side)
30-24= non-parallel side
6= non- parallel side
then
semi perimeter = 30/2 = 15
then, area by heron's formula,
area = root [15*(15-12)(15-12)(15-6)
area = root [15*3*3*9]
area = 3*3*root(15)
area= 9root 15
area = 34.85..
i hope this will help
perimeter = sum of all sides
here, 30= 12+12+(non-parallel side)
30-24= non-parallel side
6= non- parallel side
then
semi perimeter = 30/2 = 15
then, area by heron's formula,
area = root [15*(15-12)(15-12)(15-6)
area = root [15*3*3*9]
area = 3*3*root(15)
area= 9root 15
area = 34.85..
i hope this will help
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