Question

find the area of an isosceles triangle whose equal sides are 10cm each and base is 12cm​

Answer 1

Step-by-step explanation:

hope it will be helpful to you

Answer 2

To find the area of an isosceles triangle,

We use Heron's formula,

$\sf \: let \: the \: sides \: be \: a , \: b \: \: and \: c.$

$\sf \: a \: = 10 \: cm \\ \sf \: b \: = \: 10 \: cm \\ \sf c \: = \: 12 \: cm$

$\sf \: semiperimeter(s) \: = \frac{a + b + c}{2} \\ \\ \sf \implies \: \frac{10 + 10 + 12}{2} \\ \\ \sf \implies \: \frac{32}{2} \\ \\ \sf \implies \: 16 \: cm$

$\sf \: Area = \sqrt{s (s-a)(s-b)(s-c) } \\ \\ \sf \: = \: \sqrt{16(16 - 10)(16 - 10)(16 - 12)} \\ \\ \sf \: = \sqrt{16 \times 6 \times 6 \times 4} \\ \\ \sf \: = \: \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 2 \times 3 \times 2 \times 2} \\ \\ \sf \: = \: \sqrt{ {2}^{2} \times {2}^{2} \times {2}^{2} \times {3}^{2} \times {2}^{2} } \\ \\ \sf \: = \: 2 \times 2 \times 2 \times 3 \times 2 \\ \\ \sf = \: 48 \: {cm}^{2} \: \: \: ...(ans)$