Question

Find the area of an isosceles triangle whose equal sides are 13 cms and the base is 24 cms.​

Answer 1

Answer:

the area of an isosceles triangle whose sides are 13 cm and base is 24 cm is 60cm^2.

Step-by-step explanation:

step:-1) let height of a triangle be A

and base of q triangle be B

then given height and base is

A=13cm

B = 24cm

step:- 2) Now the area of isosceles triangle will be

1/2 × b × √a^2 -√b/2^2

1/2× 24×√13^2 - 12^2= 12×5

=60cm^2