Question

Find the area of an isosceles triangle whose equal sides is 13 cm and its base is 24 cm.

Answer 1

Answer:

12 cm^2

Step-by-step explanation:

a= 13 b=13 c =24  

s=( a+ b+c)/2

=( 13+13 +24) /2 = 25  

 area= √ ( s ( s-a) ( s-b) ( s-c) )

= √ ( 25( 25- 13) (25 - 13) ( 25 - 24 )

= √ ( 25* 12*12 * 1)  

= 12 cm^2

 therefore the area is 12 cm^2

Answer 2

Step-by-step explanation:

Let the triangle be ABC with AB=AC=13cm and BC=24cm

Draw AD median to BC which becomes the altitude

Now in triangle ADC,

(AD)^2+(DC)^2=(AC)^2

=>(AD)^2+12^2=13^2

=>(AD)^2=25

=>AD=5cm

NOW AREA =1/2×BC×AD

=1/2×24×5

=60

HOPE IT HELPS(*-*)