Question

Find the area of an isosceles triangle whose length is 16cmand one of its equal side is 10cm.

Answer 1

Equal sides of the isosceles triangle = 10cm
Base = 16cm

Let's use herons formula to find the area.
Area = √s (s - a) (s - b) (s - c)
Where,
a = 10cm
b = 10cm
c = 16cm

To find s:-
s = a+b+c/2
s = 10 + 10 + 16/2
s = 36/2
s = 18

Area = √s (s - a) (s - b) (s - c)
Area = √18 (18 - 10) (18 - 10) (18 - 16)
Area = √18 × 8 × 8 × 2
Area = √3 × 3 × 2 × 8 × 8 × 2
Area = 3 × 2 × 8
Area = 48cm^2

Answer 2

.Equal sides of the isosceles triangle = 10cm

Base = 16cm

Let's use herons formula to find the area.

Area = √s (s - a) (s - b) (s - c)

Where,

a = 10cm

b = 10cm

c = 16cm

To find s:-

s = a+b+c/2

s = 10 + 10 + 16/2

s = 36/2

s = 18

Area = √s (s - a) (s - b) (s - c)

Area = √18 (18 - 10) (18 - 10) (18 - 16)

Area = √18 × 8 × 8 × 2

Area = √3 × 3 × 2 × 8 × 8 × 2

Area = 3 × 2 × 8

Area = 48cm^2