Find the area of an isosceles triangle whose one side is 10 cm greater than each of its equal size and its perimeter is hundred centimetre
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Let the equal size side be x.
Then third side = x + 10cm
x + x+ 10 = 100
2x + 10= 100
2x = 90
x = 45
Now use Pythagoras theorem to solve further
Then third side = x + 10cm
x + x+ 10 = 100
2x + 10= 100
2x = 90
x = 45
Now use Pythagoras theorem to solve further
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