Find the area of an isosceles triangle whose perimeter is 32cm and it's base is 12 cm.
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Answered by
4
Isoscales triangle has two equal sides let these sides be x
So x+x+12=32
2x+12=32
2x=32-12
2x=20
X=20/2=10
So x+x+12=32
2x+12=32
2x=32-12
2x=20
X=20/2=10
Answered by
4
answer is
32-12=20
20÷2=10{equal sides}
1/2×6×8
=24
32-12=20
20÷2=10{equal sides}
1/2×6×8
=24
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