find the area of an isosceles triangle whose perimeter is 36 cm and base is 16 cm
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Step-by-step explanation:
Perimeter of isosceles triangle:
side-1 + side-2 + base
side-1 = side-2 ( in an isosceles triangle)
a + a + 16 = 36
2a + 16 = 36
2a = 36 - 16
2a = 20
a = 20/2
a = 10
The length of equal sides is 10cm.
Area:
√s(s-a)(s-b)(s-c)
s = P/2
s = 36/2 = 18
√18(18-10)(18-10)(18-16)
√18x8x8x2
√2x3x3x2x2x2x2x2x2x2
√(2x2)(2x2)(2x2)(2x2)(3x3)
2 x 2 x 2 x 2 x 3 = 48cm²
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