Question

find the area of an isosceles triangle whose two equal sides are 10 cm each and
third side is 8 cm​

Answer 1

Question =》

find the area of an isosceles triangle whose two equal sides are 10 cm each and

third side is 8 cm

Given=》

Two sides =10cm

third =8cm

Proof =》

Area of isosceles triangle =

$\frac{b}{4} \sqrt{4a {}^{2} } - b {}^{2} \\ = \frac{8}{4} \sqrt{4 \times 10 {}^{2} { }^{} - 8 {}^{2} } \\ = 2 \sqrt{4 \times 100 - 64} \\ \\ = 2 \sqrt{400 - 64} \\ = 2 \sqrt{336} \\ = 36.66$

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