Find the area of an isosceles triangle, whose two equal sides are 5
cm each and third side is 8cm.
Answers
Answer:
Step-by-step explanation:
S=(a+b+c)/2=(5+5+8)/2=18/2=9
Area =root s(s-a)(s-b)(s-c)
=root 9(9-5)(9-5)(9-8)
=root 9×4×4×1
=root 144
=12
Therefore or Hence ,Area of the isosceles triangle is 12 square mertre
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Given : an isosceles triangle, whose two equal sides are 5 cm each and third side is 8cm.
To find : area of triangle
Solution :
In an isosceles triangle median on unequal side is also perpendicular
Let say AB = AC = 5 cm , BC = 8 cm
and AD median to BC => AD ⊥ BC
=> BD = CD = BC/2 = 8/2 = 4 cm
AD² = AB² - BD²
=> AD² = 5² - 4²
=> AD² = 9
=> AD = 3 cm
Area of Δ ABC = (1/2) BC * AD
= (1/2) * 8 * 3
= 12 cm²
area of an isosceles triangle, whose two equal sides are 5 cm each and third side is 8cm is 12 cm²
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