Math, asked by matiurrahmankhaan, 11 months ago


Find the area of an isosceles triangle with base 20 cm long and each of the two equal sides 15 cm long ​

Answers

Answered by Anonymous
3

Answer:

Area =

1 \div 2 \times 20 \times 15 = 150 {cm}^{2}

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Answered by yashkirdak1
1

Answer:

50√5 cm²

Step-by-step explanation:

height of isosceles triangle

= √(same side)²-(1/2base)²

=√15²-10²

=√125

=5√5

area=1/2 ×base × height

= 1/2 ×20×5√5

=50√5 cm²

approximately=111.8 cm²

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