Find the area of an isosceles triangle with
perimeter 36 cm and base 16cm
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Answer:
as two sides of isosceles are equal
side = (36-16)/2= 20/2 =10
semi perimeter = 36/2 =18
by heron formula
√{s(s-a) (s-b) (s-c)}
√{18 (18-16) (18-10) (18-10)}
√{18*2*8*8}
√{2304}
= 48cm sq
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