Find the area of an isosceles triangle with perimeter 36 cm and base 16 cm Selina publisher solution
Answers
Answered by
0
Answer:
solutionA=48cm²
Step-by-step explanation:
b Base
16
cm
P Perimeter
36
cm
Using the formulas
A=bhb
2
P=2a+b
hb=a2﹣b2
4
Solving forA
A=1
4bP(P﹣2b)=1
4·16·36·(36﹣2·16)=48cm²
Answered by
1
Answer:
Let the congruent sides of the isosceles triangle =a.
Perimeter of the triangle =
Sum of all sides = a + a + b =36
=>2a+16=36
On solving, a =10cm
Since the height of the triangle, divides it into two right angled triangles,
a
2
=h
2
+(
2
b
)
2
=>10
2
=h
2
+8
2
h
2
=100−64=36
h=
36
=6 cm
Area of triangle =
2
1
×base×height=
2
1
×16×6=48 sq cm
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