Find the area of an isosceles triangle with perimeter 36cm and base 16cm
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Answered by
2
hi ,
given,
p = 36 cm
b = 16 cm ,
the two sides of isosceles traingle is equal so ,
p - b = two sides
36 - 16 = 20 cm
one side = 20 ÷ 2 = 10 cm
and then put the formula .
hope it will help
given,
p = 36 cm
b = 16 cm ,
the two sides of isosceles traingle is equal so ,
p - b = two sides
36 - 16 = 20 cm
one side = 20 ÷ 2 = 10 cm
and then put the formula .
hope it will help
Answered by
14
Perimeter = 36 cm
Base = 16 cm
Sum of equal sides = 36 - 16 = 20 cm
Length of one equal side = 20/2 = 10 cm
Height = {(10)^2 - (8)^2}^1/2
= (100 - 64)^1/2
= (36)1/2
= 6 cm
Now,
Area of the triangle = 1/2(base*height)
= 1/2*6*16 = 48 sq.cm Ans
<Hope it helps>
<<Please mark it as brainliest>>
Base = 16 cm
Sum of equal sides = 36 - 16 = 20 cm
Length of one equal side = 20/2 = 10 cm
Height = {(10)^2 - (8)^2}^1/2
= (100 - 64)^1/2
= (36)1/2
= 6 cm
Now,
Area of the triangle = 1/2(base*height)
= 1/2*6*16 = 48 sq.cm Ans
<Hope it helps>
<<Please mark it as brainliest>>
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