Find the area of an isoscles triangle with two equal sides as 5 cm each and the third side as 8 cm.
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IN A ISOSCELES TRIANGLE
THE AREA ACCORDING TO MY FORMULA=1/4×B√{(2A)²-(B)²}
WHERE A IS EQUAL SIDES AND B IS UN EQUAL SIDE
AREA = 1/4×8√{(10)²-(8)²}
=1/4×8×√36
=1/4×8×6
= 12 CM²
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The two equal sides are 5 cm each. The unequal side is 8 cm. Now a perpendicular is dropped from the angle between the equal sides on the unequal side.
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