find the area of an isosles triangle whose perimeter is 32 cm and base is 12 cm
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Let two common side be x
2x+12=32
2x=32-12
2x=20
X= 10
Altitude=a
A²+base/2²= x²
a²=100-36
a²=64
a=8
Area = 8×12/2
Area=48
2x+12=32
2x=32-12
2x=20
X= 10
Altitude=a
A²+base/2²= x²
a²=100-36
a²=64
a=8
Area = 8×12/2
Area=48
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