Question

Find the area of an triangle whose two sides are 24cm and 10cm and perimeter is 62cm

Answer 1

perimeter of triangle =sum of all sides(a+b+c)
a=24 b=10
let c=x
a+b+c=perimeter of triangle
24+10+x=62cm
34+x=62cm
x=62-34
x=28
area of triangle =s=perimeter /2
62/2=31
√s(s-a)(s-b)(s-c) =√31(31-24)(31-10)(31-28)
=√31*7*21*3
=√31*7*3*7*3
=21√31cm^2

Answer 2

Answer:

21√31cm^2 . hope this helps you . please mark it as the brainliest .

Step-by-step explanation:

perimeter of triangle =sum of all sides(a+b+c)

a=24 b=10

let c=x

a+b+c=perimeter of triangle

24+10+x=62cm

34+x=62cm

x=62-34

x=28

area of triangle =s=perimeter /2

62/2=31

√s(s-a)(s-b)(s-c) =√31(31-24)(31-10)(31-28)

=√31*7*21*3

=√31*7*3*7*3

=21√31cm^2