Question

find the area of an triangle whose two sides area 8cm,11cm,and perimeter is 32cm​

Answer 1

Answer:

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle = s(s−a)(s−b)(s−c)

=16×8×5×3=830 cm2

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