Math, asked by aisyah48391, 1 year ago

Find the area of an triangle with sides 40 cm,24 cm and 23 cm

Answers

Answered by shwetadarda
0

Answer:

Area = 240 sq.cm

Step-by-step explanation: To find height of triangle : Let h represent height in cm .

In triangle h draws perpendicular on side 40 cm dividing its length in x and 40-x cm

So by PGT : in one triangle h^2=(24)^2 - (40-x)^2

In other triangle h^2= (23)^2-x*2

Solving both equations we get

x = 19 cm

therefore h= 12 cm

Area of triangle= (h*b)/2 = (12*40)/2=240 Sq.cm




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