Find the area of an triangle with sides 40 cm,24 cm and 23 cm
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Answer:
Area = 240 sq.cm
Step-by-step explanation: To find height of triangle : Let h represent height in cm .
In triangle h draws perpendicular on side 40 cm dividing its length in x and 40-x cm
So by PGT : in one triangle h^2=(24)^2 - (40-x)^2
In other triangle h^2= (23)^2-x*2
Solving both equations we get
x = 19 cm
therefore h= 12 cm
Area of triangle= (h*b)/2 = (12*40)/2=240 Sq.cm
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