find the area of annulus whose inner and outer radii are 6cm and 8cm
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22
area of inner circle= π(6)^2=36π
area of outer circle= π (8)^2= 64π
so area of annulas= 64π-36π=28π=28(22/7)=88cm2
area of outer circle= π (8)^2= 64π
so area of annulas= 64π-36π=28π=28(22/7)=88cm2
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5
The areo of the annulus is 42cm
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