find the area of aob a=4,0 b=0,6
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hey your questions in not clear
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point A & point B are x- axis & y axis . so, point o is on origin i.e. (0,0)
ar (AOB) = 1/2 { X1( Y2-Y3) + X2 (Y3 - Y1) + X3 ( Y1 - Y2)}
= 1/2 [ 4 ( 0 - 6 ) +0 (0 - 0) + 0 (0-0)]
= 1/2 [ 4 (-6 ) +0 + 0 ]
=1/2 [ -24]
= -12
ar (AOB) = 1/2 { X1( Y2-Y3) + X2 (Y3 - Y1) + X3 ( Y1 - Y2)}
= 1/2 [ 4 ( 0 - 6 ) +0 (0 - 0) + 0 (0-0)]
= 1/2 [ 4 (-6 ) +0 + 0 ]
=1/2 [ -24]
= -12
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